2x^2-15x=-3x^2-4x-2

Solution for 2x^2-15x=-3x^2-4x-2 equation:

2x^2-15x=-3x^2-4x-2

We move all terms to the left:

2x^2-15x-(-3x^2-4x-2)=0

We get rid of parentheses

2x^2+3x^2+4x-15x+2=0

We add all the numbers together, and all the variables

5x^2-11x+2=0

a = 5; b = -11; c = +2;
Δ = b2-4ac
Δ = -112-4·5·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-9}{2*5}=\frac{2}{10}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+9}{2*5}=\frac{20}{10}
=2
$